Question:

Algebra 1 square roots?

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8: sqrt (16x^10)

9: sqrt (54x^11)

10: sqrt (54a^9)

11: sqrt (128x^6)

12: sqrt (-27x^5)

13:

sqrt (16x^7)

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sqrt (4x^4)

14:

sqrt (162x^6)

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sqrt (64x^2)

15:

sqrt (625x^3)

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sqrt (25x^6)

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3 ANSWERS


  1. Do your own homework.


  2. Solving these problems is simple. Here's how you should proceed:

    Before you do anything, remember PEMDAS

    In number eight, you should raise 16 to the 10th power, and then square the result.

    Use a calculator!

  3. sqrt (16x^10) = 4x^5

    sqrt (54x^11) = sqrt (9*6x^11) = 3x^5 *sqrt(6x)

    sqrt (54a^9) = 3a^4 sqrt(6a)

    sqrt (128x^6) = sqrt[(2^7) *(x^6)] = sqrt(2^7) *sqrt (x^6)= 2^3 sqrt(2) * x^3 = 8x^3 sqrt(2).

    sqrt (-27x^5)= 3x^2sqrt(-3x)

    sqrt (16x^7)       sqrt[(2^4)(* x^7)]      2^2 * x^3 * sqrt(x)

    -------------------- = --------------------    = --------------------

    sqrt (64x^2)       sqrt( 2^6 x ^2)          2^3 x

    =  [ 4x^3 sqrt(x)]  /  8x = [x^2 sqrt(x) ] / 2.

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