Algebra 2 Help please!!?

Question

And thank you. and if you can provide work... thank you to those to who got it...

(1/5)(3n+5) = [(n/2)+10]

Answer 1

(1/5)(3n+5)=[(n/2)+10 --- first try to get rid of the fractions on each side

5(1/5)*5(3n+5)=2(n/2) +2(10) - multiply by the denominator.

5(15n+25)=2n+20 -- is what you get

75n+150=2n+20 -- the above... simplified

75n+150-150=2n+20-150 -- subtract the 150 from both sides

75n=2n-130 -- Subtract 2n from both sides

73n=-130 -- divide both sides by 73

n=1.8

Answer 2

n = 90

Process:

(1/5)(3n+5) = [(n/2)+10].  Use the distributive property:

[(3n)/5] + 1 = (n/2) +10.  Gather all n's to one side of the equation:

[(3n)/5] - (n/2) = 10 - 1.  Factor out n:

n[(3/5) - (1/2)] = 9.

n[(6/10) - (5/10)] = 9.

(1/10)n = 9. Multiply both sides by 10 to get n by itself and you're done!

n = 90

Answer 3

chea.

just did the math. its 90.

you have the work from the other answers, but just to rule out the odd answer.