Algebra 2 help?!? i need help please help me!?

Question

omg.. i have a test tomorrow and here are some reviews questions i got and i can't do them i need help so i get a good test gradee

and this is cheating cause the review is not for a grade okk

please help!

how do you do...

3x+10-5x= -24

(3x^4y^2)(-2xy^3)

and (4x^2+3x-6)-(x^2-2x-4)

Answer 1

3x+10-5x=-24

-2x+10=-24

-2x=-34

x=17

(3x^4y^2)(-2xy^3)

-6x^5y^5

(4x^2+3x-6)-(x^2-2x-4)

4x^2+3x-6-x^2+2x+4

3x^2+5x-2

Answer 2

3x+10-5x=-24

    -10       -10

3x - 5x=-34

-2x=-34

x= 17

(3x^4 y^2)(-2xy^3)

multiply your coeffiecients (3 and -2)

add your exponents (x^4 + x)  and (y^2 + y^3)

-6x^5y^5

(4x^2+3x-6) - (x^2-2x-4)

distribute the minus sign to the second half

(4x^2+3x-6) -x^2 +2x+4

now combine like terms

3x^2 + 5x - 2