Question:

Algebra 2 problem for 10 points (multiples answers) unit#10?

by Guest57042  |  earlier

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1 the graph of which equation is a circle

a 5x^2+10x=9+5y^2

b 5x^2-10x=0-5y^2

c 5x^2+5x+y^2=9

d 5x^2+10x+5y=9

2 solve the system of equations by graphing x^2+y^2=16 and y=-X-4

a (4,0),(0-,4)

b (0,-4),(-4,0)

c (-4,0),(0,-4)

d (0,4),(4,0)

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3 ANSWERS


  1. Problem 1:

    B.  This can be simplified into (x-1)^2 + (y-0)^2 = 1

         The other ones cannot be factored into perfect squares.

    { A. cannot be a circle because y^2 would be negative if moved over to the side with x^2.  C. cannot be a circle as x^2 and y^2 do not have the same coeficient.  D. cannot be a circle because there is no y^2.}

    Problem 2:

    B & C (are the same thing).  You can solve this one algebraically by substituting (-X-4) for "Y" in the first equation, or you can just graph the two equations and analyzed it visually.


  2. 1.a&b

    2.you ,please, draw the graph yourself,as it is not possible to

    show this here.

    the solution is (b);

    Hope it will help.


  3. 1. b

    2.  b

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