Algebra 2 problem that I just can't solve, please help . . .?

Question

I've been staring at this problem for hours and I still can't figure it out. It's due tomorrow, and the teacher doesn't accept work that isn't finished nor is he in his room before school starts. I just really struggle with Algebra and would appreciate if someone was able to answer or give me a hint on this.

Solve this equation: x + 2x +3 = 75

(this next one is non-related to the one above)

6)

Here is a problem and three related equations.

Anita buys 6 large beads and 20 small beads to make a necklace. Ivan buys 4 large and 25 small beads for his necklace. Jill selects 8 large beads and 16 small beads to make an ankle bracelet. Without Tax, Anita pays $2.70, and Ivan pays $2.85. How much will Jill pay?

6L + 20S = 270 (equation 1)

4L + 25S = 285 (equation 2)

8L + 16S = J (equarion 4)

a) what do the variables L, S and J represent?

b) what are the units of L, S and J?

c) what does equation 1 represent?

Answer 1

equation

3x+3=75

3x=72

x=24

jill will pay 2.64

L= large beads = 15cents each

s = small beads = 9cents each

l s j are all cents

equation 1 is how represents the amount payable by anita

Answer 2

For your first problem you need to seperate the x's from the normal numbers. Just subtract three from 75. This gives you x+2x=72, or 3x=72. Then you simply divide 72 by 3 to get x.

Your second problem involves more work, but the idea is similar. For equation one, subtract 20S from the side with 270. Then you have 6L=270-20S. Next divide both sides by 6 to get L by itself. This gives you L=(270-20S)/6. Now you know what L equals. Although it isnt a simple number, you can substitute into equation two to find the value of S. When you know both S and L you can then use equation three to find J (how much Jill paid).

Hope this helps!

Answer 3

x+2x+3=75 == 3x + 3= 75 minus three from 75 so 3x=75 divide by 3 on each side and the answer = 25

i would help you with the next one but i have to write these things down and it would tak alot of time im really sorry.

my advice is ask anyone because this is simple math, freinds, family, anyone.

study the questions harder or use a math book, they really are simple.

anyways good luck!

Answer 4

2x+x+3=75

   ^^^

is 3x+3=75

        -3   -3

    3x = 72

           72 divided by 3 = x !



P.s. this is algebra 1! < i know cuz i had to review this for 2yrs! (i didn't flunk i just didn't get it when i had a chance to start geometry)

Answer 5

I wish you would have separated this into two questions on Yahoo.  I'll answer the first.  x+2x+3=75

combine the x's to get 3x+3=75

subtract both sides by 3 and you get 3x = 72

divide each side by 3 and you get x = 72/3 = 24

Answer 6

you use systems of equations....substitution, i think would be the easiest...first you take an equation, 1 or 2, and add it to the other equation to get one variable instead of two...so say you want to get rid of the variable (L) and start with equation 1....you would multiply the entire second equation by negative (3/2) to get a negative 6L in equation to to cancel out...then you have to multiply every other term in eq 2 by -(3/2)....and get -17.5S=-157.5 and S=9 after adding eq1 to eq2. you can now substitute 9 in for S in lets say eq. 1, to find L....so 6L=90, L=15...so to find out how much jill spends you plug in 15 for L and 9 for S in eq. 3, and Jill spends...120+144=$2.64 moving the decimal back 2 for the dollar amount...i assume you can do the a) b) and c)...and the equation above is 3x+3=75..3x=72....x=24....there....

Answer 7

x + 2x + 3

3x = 72

x=24

Answer 8

First the equation. The 'trick' is to get one unknown combined and to one side, and known's to the other.

x+2x+3 = 75  <==isolate "x's"(subtract 3 from each side)

x+2x=75-3 <==combine like properties

3x = 72 <==divide both sides by 3 to get 1x

x=24

check 24+(2)(24)+3=75

           24+48+3=75

           75=75

6./

a) Variables L=large beads, S=small beads and J=cost (in pennies--no $ sign)

b) Units of L and S are beads. J = money

c.) Equation 1 is Anita's part in all of this.