Algebra/Geometry help please!!!!?

Question

please tell me how to do this step by step.

directions:

You are given an equation of a line and a point. Use substitution to determine whether the point is on the line.

27) y = x - 4; A(5,1)

29) y = 3x + 4; A(7,1)

Answer 1

27)     x=5, y=1

     1=5-4  yes

29)     x=7, y=1

       1=3(7)+4=25, no

Answer 2

5 is x and 1 is y

1=5-4

1=1

On the line

1=3(7)+4

7=21+4

7=25

not on line

P.S. I did this for my homework tonight so i know how because i asked my teacher personally because i had problems too

Answer 3

whats so hard about it just plugin the values in the equation and see if right hand side=left hand side

y = x - 4; A(5,1)

5 is the x coordinate and 1 is the y coordinate

1=5-4

1=1

so the point lies on the line

29) use the same method for this question

y = 3x + 4; A(7,1)

1=3(7)+4

1=21+4

1=25

since right hand side does not equal left hand side so the point does not lie on the line

Answer 4

Ok this problem is actually very easy. Point A has two coordinates x=5 and y=1 in problem 27. all you have to do is substitute 5 for x and 1 for y into the equation, and if the two sides equal each other, than the point is on the line. So in problem 27, 5-4=1 and y=1 therefore point a is on the line. For problem 29, 3(7)=21 and then 21+4=25 and y=1 therefore in problem 29, point a is not on the line. If you need anymore help just ask

Answer 5

Basically all you need to do is "plug-in" the points given on the right to the equations on the left.

A point is defined (roughly, in 2-D) as simply: (x,y), where x is a position going left and right and y is a position going up and down.

Ex: (-5, 10) Means you go -5 units (or 5 units to the left of the origin) and 10 units up. Your point is a position in space.

So when you plug in the numbers, you just need to substitute anything in the "x" position of your given coordinate point (A) into all "x"s and anything in the "y" to the "y"s. So:

27) y = x - 4; A(5,1)

(5,1) => (x,y)

x = 5

y = 1

Substiute x = 5 and y = 1 into your equation:

1 = 5 - 4

1 = 1

Since both sides of the equation are equal, the point A(5,1) lies on the line.

29) y = 3x + 4; A(7,1)

(7,1)=>(x,y)

x = 7

y = 1

Equation becomes: 1 = 3(7) + 4

1 = 21 + 4

1 = 25

Since both sides of the equation are not the same, the point A(7,1) is not on the line.

Answer 6

easy! plug 5 for x and 1 for y

27)1 = 5-4  YES!

29)1 = 3(7) + 4

     1= 21 + 4

     1= 25 NO!!!!