Algebra HELp PLEASE!!?

Question

how do you do..

directions are to solve..

-8p -8(3 -p) = -15

and

1/5 + 2/5 (5 -3a) = -3

Answer 1

-8p - 8(3-p) = -15 (same as -8p + -8(3-p) = -15

-8p - 24 + 8p = -15  (distribute the -8 to the (3-p))

-24 = -15    (combine like terms; -8p + 8p = 0)

-24 does not equal -15, so the answer would be no real number.

1/5 + 2/5 (5-3a) = -3

1/5 + 2 - (6/5)a = -3    (distribute 2/5 to (5-3a))

2 1/5 - (6/5)a = -3    (just add the 1/5 and 2)

5 1/5 - (6/5)a = 0    (add 3 to both sides)

5 1/5 = (6/5)a    (add (6/5) a to both sides)

26/5 = (6/5)a    (change 5 1/5 to an improper fraction)

26/5 / 6/5 = a    (divide both sides by 6/5 to get a alone)

26/5 * 5/6 = a    (change to a multiplication problem to solve)

13/3 = a    (cancel the fives and the 26&6)

*update*  looking through the other answers, the second one would be a LOT easier if you multiply by 5 first.

Answer 2

1) -8p - 8(3-p) = -15

-8p - 24 + 8p = -15

0 = 9

the answer is "No Real Number"

2) 1/5 + 2/5 (5-3a) = -3

1/5 + 10/5 - 6/5a = -15/5

-6/5a = -26/5

a = 4

Answer 3

multiply it out

-8p - 24 + 8p = -15

24=-15 is a contradiction

for the second one, multiply through by 5

1 + 2(5-3a)= 75

1 + 10 - 6a = 75

-6 a = 64

a = -(64/6) = - (10 +2/3)

Try doing your own work now.