Question:

Algebra Help Please ?

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How do you solve this problem 8+2x<6x-20

I tried to subtract the 2 from 6 and work my way through but it only gave a -1.5

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3 ANSWERS


  1. add 20 to both sides: 28+2x&lt;6x

    subtract 2x from both sides: 28&lt;4x

    divide by 4: 7&lt;x


  2. 8 + 2x &lt; 6x - 20

    2x - 6x &lt; -20 -8

    -4x &lt; -28

    divide both sides by -4, remember that you have to change the sign when you do this

    x &gt; 7

  3. 8+2x=6x-20

      -2x  -2x

    8=4x-20

    +20  +20

    28=4x

    /4  /4

    7=x
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