Question:

Algebra II Help!!! ASAP thnx ?

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Melissa and roy both sell cars at the same dealership and have to meet the same profit goal each week. Last week, roy sold only three cars and he was below his goal by $2050. melissa sold seven cars, and she beat her goal by $1550. assume that the profit is approx the same for each car they sell.

heres the question:

what was the profit goal...and

how many more cars must roy sell to be within $500 of his goal?

thnx!!

and plz show ur work

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1 ANSWERS


  1. 3x=g-2050

    7x=g+1550

    Take the first equation and solve for g

    3x+2050=g

    Plug that in for g in the second equation

    7x=3x+2050+1500

    7x=3x+3550

    4x=3550

    x=3550/4=887.5

    Each car gives a profit of about $887.50.  If Roy sells one more car, he will be within (2050-887.5) of his goal ($1162.5).  If he sells 2 more cars, he will be within (1162.5-887.5) of his goal ($275)

    _/

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