Algebra II help please?

Question

I need help on this question...

Write the equation of each line.

1. m=4; contains (3,2)

2. m=0; contains (3,0)

I have no idea how to do these so any help would be great. Thanks!

Answer 1

Dont you have a teacher? lol

Answer 2

1) y = 4x - 10

2) y = 0

Answer 3

http://en.wikipedia.org/wiki/Slope

(scroll down to algebra)

m is the slope

Answer 4

y=mx+b

you've got y

you've got m

you've got x

just find b!

Answer 5

1. Y=4x                  go up 3 then over 2 then from that point go 4 up and 1 over to continue the line.

2. Because m, which is the slope, is zero the line is horizontal.

Answer 6

y=2x-4

i don't know if that is right but that is the equasion of the line that goes through both points

Answer 7

use the equation y-y1 = m(x-x1)

where m is given (gradient)

x is just x the letter... and x1 is 3

y is just the y letter and y1 is 2 in one case and 0 in case 2

sub the values and you should be alright..

Answer 8

alright well from what i remember m is the slope so for

1: plot the point (3,2) on a grid and then use the slope, so this would be a line with positive slope. One point would go up 4 and one to the right and another down 4 and one to the left, connect the dots and that is #1

2: This is a vertical line on the point (3,0) go straight up and down and that should be that line.

Not positive but pretty sure

Answer 9

1. y=mx + b   is standard form

plug in 3 which is x and 2 which is y into the equation

2=3m+b     the slope is m, plus that in

2=3(4) + b   solve for b which is the y intercept (where the line will cross the y axis)

b=-10

so u write it as y=4x-10

2. The slope is 0, which is different from no slope so dont mix that up

y=0     0 is the y intercept