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[Algebra] Simplify without decimals: (2^π-2) ÷ (2^π+2) ?

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In algebra, simplify without decimals:

(2^π-2) ÷ (2^π+2)

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  1. Hi,

    (2^π-2) ÷ (2^π+2) =

    2^(π-2)

    ---------- =

    2^(π+2)

    2^((π-2) - (π+2)) =

    2^(π - 2 - π - 2) =

    2^(-4) =

    1/2^4 = 1/16 <==ANSWER

    I hope that helps!! :-)

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