Algebra/geometry math help?

Question

how would you do these problems? (showing work):

1. write an expression for the perimeter of a rectangle with length l = 2x + 3 and width w = x - 2.

2. write an expression for the area of a square with side s = 2x + 5.

3. find the diagonal of a rectangle with l = 40 and w = 55.

Answer 1

1. Perimeter means to add all the outsides, so length + length + width + width

2x + 3 + 2x + 3 + x - 2 + x - 2

= 6x + 2  units

2. To find area of a square, multiply side x side :

(2x + 5) (2x + 5 ) = 4x^2 + 20x + 25 un^2

3.  To find the length of a diagonal, use pythagorean theorem

40^2 + 55^2 = c^2

4625 = c^2

Take the square root

68.0073525 = c

Good luck to you !