Algebra help its easy just im not good at it?

Question

write the algebric equation then solve

five time the sum of a number and nine is thirt nine

nine less three times the difference of a NUMBER AND FOUR IS THIRTY SIX

the sum of two consecutive odd integers is 44

Answer 1

Just remember the following rules

is means "="

times = multiply

sum = add

less = subtract

difference = subtract

a)

5 * (x + 9) = 39

5x + 45 = 39

5x = -6

x = -6/5

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b)

this one is trickier, start from the inside and work out

difference of a number and for means

x - 4

three times that

3(x - 4)

nine less than that

3(x - 4) - 9

is 36

3(x - 4) - 9 = 36

3x - 12 - 9 = 36

3x - 21 = 36

3x = 57

x = 19

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c)

If x is an odd integer, x + 2 is the next consecutive odd integer, so...

x + (x + 2) = 44

2x + 2 = 44

2x = 42

x = 21

So the integers are...

21 and 23

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EDIT

Sorry, I mis-read the second question.

difference of a number and for means

x - 4

three times that

3(x - 4)

nine less that

9 - 3(x - 4)

is 36

9 - 3(x - 4)  = 36

9 - 3x + 12 = 36

-3x + 21 = 36

-3x = 15

x = -5

Answer 2

5(x+9) = 39

5x + 45 = 39

5x = -6

x = -6/5

9-3(x-4) = 36

9-3x+12=36

-3x=15

x=-5

(x+1) + (x-1) = 44

x=22

and the consecutive odd numbers = 21 and 23