Algebra help please?

Question

4x+49<9-x

Algebra is not my subject and everytime i do these kind of problems it gives me a negative

Answer 1

ok so first you have

4x+49&lt;9-x

add x to both sides

5x + 49&lt; 9

then subtract 49 from both

5x&lt; -40

then divide by 5

x&lt;-8

:]

dont forget that if you divide by a - you have to switch the sign

Answer 2

x=negative 8

Answer 3

I&#039;m not quite sure if this is correct because I just calculated it in my head but I think it&#039;s x&lt;-8

4x+49&lt;9-x

4x+x&lt;9-49

5x&lt;-40/5

x&lt;-8

Answer 4

This is how it is done step by step

4x+49-49&lt;9-x-49(subtract 49 on both sides)

4x&lt;-x-40

4x+x&lt;-x-40+x(add x on both sides)

5x&lt;-40

(5x/5)&lt;((-40)/5)

x&lt;(-8)

Check the answer: -

4(-8)+49=17

9-(-8)=17

so 4x+49&lt;9-x

Answer 5

Move x&#039;s and numbers to different sides: 5x &lt; -40

Simplify: x &lt; -8.

By the way, x can be negative. Just can&#039;t say something like -5 &gt; 8.

Answer 6

*add x to each side*

4x+x+49&lt;9

       =

5x+49&lt;9

*subtract 49 from each side*

5x = -40

*divide each side by 5*

x = -8

It&#039;s supposed to be a negative, you didn&#039;t do anything wrong.

Answer 7

maybe this will help hotmath.com

Answer 8

THere is nothing wrong with getting a negative.  I got x&lt;-8, so it can be -9,-10,etc.

Answer 9

4x + 49 &lt;9-x

     - 49   - 49

4x&lt;-40-x

+x     +x

5x&lt;-40

x&lt;-8

* i totally understand your problem. i took algebra two years ago. it was sooo hard for me. but compared to alg. 2 it&#039;s sooo easy :)

Answer 10

the answer is x= -8

Answer 11

4x+49&lt;9-x-----&gt; 5x+49&lt;9 ----&gt; 5x&lt;-40 -----&gt; x&lt;-8