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Algebra help ?

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Please help me with these problems, I'm soo confused??

Find the slopes of the line through the following points:

(3,6) (-2,-4)

(0,2) (-6,8)

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  1. it pretty easy, you have to use the slope formula: y2-y1 divided by x2-x1.  so -4 minus 3 over -2  minus 6.  Once u have divided them you have the slope.


  2. For this question, your formula is (y2-y1)/(x2-x1).  Coordinates are given in an (x,y) pattern. Simply assign each set of points with y1, x1, etc.  Your x1 = 3, x2 = -2, y1 = 6, y2 = -4.  So: (-4) - (6) / (-2) - (3) = (-10) / (-5). This is your slope.

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  4. -9

  5. Well it's no good learning THESE PARTICULAR slopes, you have to learn how to do this and why it works.  So here's a brief lesson.

    Slope is defined as rise over run.  That means how much a line rose (or fell) in a given distance along the ground.  Like if you were on a ramp, and for every step forward you took, you rose an inch in elevation, that ramp would have a slope of 1 over 12 meaning for every twelve inches forward it rises one inch in height.  If you lay down on the ground and looked at the ramp's edge, you'd see a line with a one over twelve rise, or a slope of one over twelve.

    A steeper ramp might rise 4 inches for every foot forward.  There are rules about how steep ramps can be at public buildings for wheelchairs, and that steepness is expressed this way, "a slope of not more than so many inches rise for every foot forward."

    So the "rise" is how much it rises or falls and the run is in how much forward distance we're talking about.  If the units of rise and run are the same, like both in inches, then you can leave off the units and just say the slope is 1 in 12 or 1 in 6 or whatever meaning one inch rise for every 12 inches run, or in six inches run, etc.

    Now to this algebra problem.  Each point is expressed as an x coordinate, then a comma, then a y coordinate.  The x is how far along the x axis, the one along the bottom, and the y is how far up the y axis, the one that goes up the side.  So the first point is at 3 on the x axix, or 3 units along the bottom from zero, and at six units up the y axis from zero.  So this point is three units right and six units up from zero.  The second point is two units to the left of zero and four units down.  So we need only to figure out the difference in height of the two points and put that number in the top and figure out the difference between the two x values and put that number in the bottom, and we'll have the slope.

    So the height goes from up six to down four, for a change of negative 10.  The horizontal position goes from right three to left two, for a change of negative 5.  So the slope is -10/-5, which simplifies to 2.

    Rise over run.

    Ok, go get the rest now.

  6. For the first one, the slope would be 2 because you do y1(first y value)-y2(second y value) over x1(first x value)-x2(second x value):

    10/5 = 2

    The second one would be -1 (-6/6). I used the same formula as the first one.

    If you still don't understand it, ask your teacher.
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