Algebra help........?

Question

(1) -4 + 5x = -6x - 114

(2) 6(-10 - 7x) = -438

(3) -4 + 5x = -6x - 114

(4) 4x^2 + 2x = 0

(5) 3x^2 + 11x -4 = 0

Please show your work and check your answers. Thanks in advance!

Answer 1

help or u want the answer.......

gather all the 'like terms' on 1 side and solve

get all the x terms on 1 side and the integer terms on the other side

Answer 2

(1) -4 + 5x = -6x - 114

-4 + 11x = -114

11x = -110

x = -10

(2) 6(-10 - 7x) = -438

-60 - 42x = -438

-42x = -378

x = 9

(3) -4 + 5x = -6x - 114

This problem is the same as number 1. See above

(4) 4x^2 + 2x = 0

x(4x + 2) = 0

2x(2x+1) = 0

x = 0 or -1/2

(5) 3x^2 + 11x -4 = 0

Plug into quadratic formula and you get -4 and 1/3

Answer 3

(1) -4 + 5x = -6x - 114

    11x = -110

        x = -10

(2) -60 - 42X = -438

        -42x = -378

            x = 9

(3) same as number 1

(4) (2x + x)(2x + x) = 0

Answer 4

(1) -4 + 5x = -6x - 114

     11x=118, x= 118/11

6(-10 - 7x) = -438

-60-42x=-438

-42x=-438+60

-42x=-378, x=-378/42

#3 is the same as #1

4x^2 + 2x = 0

4x^2=-2x

divide both sides by 2:     (4x^2=-2x)/2

then divide both sides by x: (2x^2=-x)/x

x=-1/2

3x^2 + 11x -4 = 0, use the quadratic equation to solve, good luck