Algebra homework help?

Question

OK, so I completely don't get this problem. It's completely different from all the other ones in my homework. Also could you not just give me the answer. Show me the steps so I know how to do it.

Two numbers differ by 57. Their sum is 185. Find the numbers.

So I guess you have to set up a problem?

Thanks for your help!!

Answer 1

64 and 121.

i just guessed and checked. i took 121 and subtracted 57 from it. i got 64. 64 plus 121 equals 185.

Answer 2

um...i think you would do

x+x-57=185

2x=242 (add 57 to both sides)

x=121 (divide by two)

one number is x and the other is x-57

so the two numbers are: 64 and 121

Hope its right!

Answer 3

The trick is: if two numbers differ by 57, then you can express them like this:

First number: X

Second number: X+57

Once you hit on that trick, the rest is not all that hard.  If the sum is 185, you can express that this way:

First number plus second number equals 185.

X plus (X+57) equals 185.

I'll let you do the rest, since you ask to not just be handed the solution.

Answer 4

ok so..

64 and 121

x+x-57=185

Subtract 185 from 57 and you get "128"

then since there are two numbers divide by "2" which = 64, so your first number is 64. subtract 185 from 64 and VOILA!

hope that helped (sorry it was sorta hard to explain_

Answer 5

x+(x+57)=185

2x+57=185

2x+57-57=185-57

2x=128

x=64

replace x with 64 and check

64+(64+57)=185

64+121=185

check 121-64=57

the two numbers are 121 and 64