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Algebra problem for school again ?

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-4c-11=4c+21

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  1. -4c=4c+32

    -8c=32

    c=-4


  2. c= - 4

    you add the - 4c to both sides of the equation to give you - 11= 8c + 21. then you subtract 21 from both sides to give you - 32= 8c. then you divide bothe sides by 8 giving you c= - 4

    remember. in algebra if you do something to one side of the equation you have to do it to the other

  3. -4c - 11 = 4c + 21

    What you have to remember is that whatever you do to the left side of an equation, you also do to the right side.

    Add 4c to each side

    4c - 4c - 11 = 4c + 4c + 21

    Combine like terms

    - 11 = 8c + 21

    Now subtract 21 from each side

    -21 - 11 = 8c + 21 - 21

    And Combine like terms again

    -32 = 8c

    Finally divide each side by 8

    -32/8 = 8c/8

    -4 = c

    So your answer is...

    c = -4

  4. -8c=32

    c=-4

  5. -4c-11=4c+21

    Add 11 to both sides (what you do to one side, you must do to the other.  so you are left with

    -4c=4c+32

    Now subtract 4c from both sides and you are left with

    -8c=32  Because -4c-4c=-8c.  a negative minus a negative is always negative

    Now Divide -8 from both sides and you get

    c= - 4

  6. C=-4

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