Algebra problems? With Fractions!?

Question

ok i took algebra last year and i just completely forgot this stuff!

like i have this problem

X+3 over 2 = 3 or X+3/2 =3

can someone give me the steps on how to do this? please help!

Answer 1

Now your question confuses me.

Is the problem X+3/2=3 or (X+3)/2=3

If it is X+3/2 = 3, then all you do is isolate the X by subtracting 3/2 from both sides leaving you with X=3/2 or 1.5

Now if your problem is (X+3)/2 = 3, then all you do is isolate the X by multiply the 2 from both sides: X+3 = 6. Next you subtract 3 from both sides to isolate the X leaving you with X=3.

Hope this helped.

Answer 2

(x+3)/2=3

x+3=6

x=3

x+(3/2)=3

x=3/2

Answer 3

x+3

-----..=3

..2

Multiply the whole equation by 2.

x+3 = 6

=x=6-3

=x=3

Check.

(3) + 3 = 6

Now take a wild guess if this will equal to 6. :P

6=6

Answer 4

Here it is:

x + 3/2 = 3

First, multiply 2 to both sides leaving x + 3

x + 3 = 6

Then subtract 3 to both sides so that x will be by itself.

x +3 = 6

   -3   -3

-------------

x = 3

Final answer is x = 3.

Hope this helps. =)