Algebra questions...?

Question

can you guys please help me with these equations?

1.simplify: (3a^2b)(2a^3b^2)

2.simplify:8x^3y^2

_________

12xy^5

I got 4x^2y^3 for that one but i am not sure.

3. x+y=8

x-y=2

I have no idea how to do number 3.

thanks..

Answer 1

1. i assume you mean (3a^2 * b)(2a^3 * b^2)

you'll get 6 * a^5 * b^3

2. you can't simplify that!

3. using x - y = 2, you get x = y + 2

sub this into x + y = 8, you'll get:

(y + 2) + y = 8

2y + 2 = 8

2y = 6

y = 3

x = 3 + 2

   = 5

Answer 2

I  have  no  idea.  Sorry.  You  can  go  to  some  maths  Websir=tes  on  the  net  for  Help.

Extremely  Sorry.

Answer 3

1. 6a^5b^3

2. 2x^2/y^3

3. solve for x, in the eq. x-y = 2

x=2+y now substitute this value of x into eq x+y=8 and you get

2+y+y=8, simplify

2y=6

y=3

Now put in 3 in place of y and you should get x=5

Answer 4

1.simplify: (3a^2b)(2a^3b^2)

***this only means multiply

= 3(2)(a^2+3)(b^1+2)

= 6a^5b^3

2.simplify:8x^3y^2

_________

12xy^5

***following the rules of law of exponent and division

.     .2(4)(x^3-1)(y^2-5)

.     ._________

.     .3(4)

***we get

.     .2(x^2)(y^-3) / 3

*** since we always follow the rules on positive exponents just invert it. So we get

.     .2x^2 / 3y^3

3. x+y=8

x-y=2

***use substitution method.

eq1: x + y = 8

eq2: x - y = 2

*** I will use eq2 first...

eq2: x = y + 2

***then substitute the answer to eq1. We get.

eq1: (y + 2) + y  = 8

***then

eq1: 2y + 2 = 8

***next

eq1: 2y = 8 - 2

***divide both side to the numerical coefficient 2

eq1: 2y/2 = 6/2

***then

eq1: y = 3

***final substitution

eq1: x + 3 = 8

***so we get

x = 5

while

y = 3

Answer 5

1. (3a^2b)(2a^3b^2) = 6b^3a^5

2. 8x^3y^2 = 8y^2x^2

Answer 6

3. x+y=8

    x-y=2

from first equation, we get

x=8-y

putting the value of x in second equation,

8-y-y=2

-2y=-6

y=3

x=8-y=5

check:  x+y=5+3=8

x-y=5-3=2