Algebra word Problem??

Question

Elissa wants to set up a rectangular dog run in her backyard. She has 48 feet of fencing to work with and wants to use it all. If the dog run is to be x feet long, express the area of the dog run as a function of x.

Answer 1

Area= x(24-x)

It's because whatever you don't use for x, will be used for the other dimension.

Answer 2

Showing a little work to make it make sense

Perimeter = 48 = sum of all sides = 2x + 2W

Area = x * W

Solving for W in 1st equation = (48 - 2x)/2 = w

w= 24 - x

Subbing this into the bottom one

Area = x(24- x) = 24x - x^2, whichever form you like

Answer 3

Basically what you need to do is you take one thing as x, like the length.

Now, the breadth should be (48-2x)/2 [there are two instances of breadth, and perimeter=48]= 24-x.

Area= L * B= x(24-x).

Its just a function, so no solving is needed, so this will work for any real value of x < 12.

Answer 4

Suppose the width of the rectangular dog run is y feet.

Now, 2(x+y)=48  [from the given condition]

or, x+y=24

or, y=24-x

Now the area of the dog run=xy sq.ft.=x(24-x) sq.ft.

[putting the value of y]

This is how you can express the area of the dog run as a function of x.

Answer 5

area of dog run = xft{(48/2 -- x)ft} = (24x -- x^2) ft^2