Aluminum metal shavings (10.0g) are placed in 100.0 ml of 12.00 measured at STP, which can be produced?

Question

2.Aluminum metal shavings (10.0g) are placed in 100.0 ml of 12.00

molar hydrochloric acid. What is the maximum volume of hydrogen,

measured at STP, which can be produced?

Balanced: 2 Al 6 HCl = 2 AlCl3 3 H2

Answer 1

Moles HCl = 0.100 L x 12.00 M = 1.200

Moles H2 = 1.200 / 2 = 0.600

V (H2) = 0.600 x 22.4 =13.4 L