An STP volume of 564 liters of oxygen is produced in the reaction?

Question

2N205(g) = 4NO2(g) O2

What volume of nitrogen dioxide is also produced if it is measured at 25 degrees Celsius and 1.00 atm?

the answer is 2.46 x 10^3 L.

Please explain the equation on this question. because I'm getting numbers all over the place.

Answer 1

Volume NO2 at STP ( p = 1 atm and T = 273 K ) = 4 x 564 = 2256 L

p1V1 / T1 =p2V2 /T2

1 x 2256 /273 = 1 x V2 /298 K

V2 = 2462 L => 2.46 x 10^3 L