An aerosol can of deodarant has a volume of

Question

an aerosol can of deodarant has a volume of 150cm^3 the contents of the can exert pressure of 9.0x10^2 kPa at 27 degrees celcius

how many paprticles are present in the can

and if the contents of the can are transferd to a 200cm^3container what will be the temp if pressure drops 6.0x10^2kPa

Answer 1

T = 27 + 273 = 300 K

p = 900000 Pa / 101325 = 8.88 atm

n = pV/RT = 8.88 x 0.150 L / 0.0821 x 300 =0.0541 moles

particles = 0.0541 x 6.02 x 10^23 = 3.26 x 10^22

p2 = 600000 / 101325 =5.92 atm

p1V1/ T1 = p2V2 / T2

8.88 x 0.150 / 300 = 5.92 x 0.200 / T2

0.00444 = 1.184 / T2

T2 = 267 K =>  - 6 °C