An airplane flies 200 km due west from city A to city B and then 360 km in the direction of 35.5° north of wes

Question

(a) In straight-line distance, how far is city C from city A?

(b) Relative to city A, in what direction is city C?

Answer 1

ABC is the Triangle.

AB=c= 200

BC=a=360

Angle B = 35.5 degrees.

Use the Cosine Formula to get AC= b.

b^2=a^2 +c^2 - 2ac Cos B.

b^2 = 360^2 + 200^2 - 2 x 360 x 200 x Cos 35.5

the value of b is the distance.

For finding the direction of city C

again use the cosine rule and find angle A.

Bye.