Question:

An easy 10 points right here?

by  |  earlier

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The problem asks to find the distance between the points:

(2k, 4k), (3k, 6k)

So I did:

D = square root of (k² + (2k)²)

...= square root of (5k²)

...= square root of (5) * k

...= k * square root of (5)

But the answer says its |k|squareroot(5).

Does it have to do with when

square root of (5k²) has squareroot(k²) therefore k must be a positive number?

but then why can't the person first square the k, then take the square root?

Thank you all in advance.

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6 ANSWERS


  1. distances can't be negative......simple as that

    even if k is negative, there will be a positive distance between the two points


  2. D = √(2k-3k)² + (4k-6k)²

       = √k² + 4k²

       = √5k² = √5 x √k²

       = k√5

  3. Yes its right. We do not know if k<0 or k>0. But we do know the distance ca never be negative. So |k| rt5 is correct.

    Say of the points are in Quad 3 the k<0 but distance is ia not<0

  4. Suppose k is -2

    Then the distance between (-4, -8) and (-6, -12)

    is the same as the diatance between (4, 8) and (6, 12) when k is +2.

    And since distance is always positive, the answer is |k| sqrt(5)

      

  5. there are 2 cases

    k is positive or zero in which case case k *sqrt(5) is correct

    but k could be -ve. this case the points are in 3rd quadrant and

    k * sqrt(5) is -ve and so we need to take |k| sqrt(5)

    |k| sqrt(5) is positive and correct for all k

    so |k| sqrt(5) is correct ans


  6. actually...the answer can be improved to |k√5| because it could be |k|(±√5) if it took the value |k|(-√5), the answer would not be accepted.

    other than this, the reasons provided by other members ie distance cant be negative in value, would suffice (:

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