An object with an initial velocity 8m/s moves along a straight line with constant acceleration ?

Question

and travels 640 m in 40 s. For the 40-s interval, find the final velocity and the acceleration of the object

Answer 1

S = ut + 0.5(a)(t^2), where u is the initial velocity, and a is the acceleration and S is the distance moved.

By putting in figures, you'll get

640 = (8)(40) + 0.5(a)(40x40)

Thus, a = 0.4 m/s^2

For the final velocity, we can simply use v = u + at

Where v is the final velocity, and the rest being as above.

Thus, v = 8 + (0.4)(40)

Solving, v = 24 m/s