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An oxide of As consists of 75.5% As, what is its empirical formula?

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An oxide of As consists of 75.5% As, what is its empirical formula?

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  1. The compound will consist of:

    As  75.5%

    O : 24.5%

    Divide each by its atomic mass

    As  75.5/74.922  = 1.007

    O   24.5/15.999 = 1.531

    Ratio is As: O =  1:1.5

    or As : O = 2:3

    Empiric formula = As2O3

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