Analytical geometry ?

Question

how to solve A(1,-3) to B(-2,T) which is perpendicular to a line with slope 1.5

ive done ....

this so far

y2 - y1

-----------

x2-x1

= T - - 3

------------------

-2-1

= T + 3

----------------- = 3/2

-3

=-9 = 2t + 6 (i cross multiplyed above)

-2t =6 +9

-2t = 15

t = 15/2

= 7.5

however the answer is -1 not 7.5 - what have i done wrong?

Answer 1

As I recall, the slope of a line PERPENDICULAR to a line with slope = a is -1/a. So you should set the slope to be -2/3, instead of 3/2 in step 3. Try that out. You are solving for the slope of a parallel line :)

Happy solving!