Another PSAT math problem...sorry...?

Question

I'm sorry for asking all these questions, I just need some extra help.

In a certain class, exactly 2/3 of the students applied for admission to a 4 year college and, of these, 1/8 applied also to a 2 year junior college. If more than one student applied to both 4 year and 2 year colleges, what is the LEAST number of students who could be in this class?

Answer 1

Well, if you have at least one student applying to the 2 yr college, that means that there would be at least 8 students applying to the 4 yr college. And 8 is 2/3 of 12.

But, since there is more than one student applying to the 2 yr one, then there has to be at least double that, 24. My answer is 24.

Answer 2

There must be at least 24 students.

More than one would have to be at least 2 students.

2/3 * 1/8 = 2/24 = 1/12 of the students in the class applied for both.

1/12 of 24 is 2, which is the least number of students possible, therefore 24 is the minimum number of students there could be.