Another inequalities question?

Question

I have another math inequalities question....

[61 + 20x] + 32 > 51

Can anyone explain it to me step by step

Answer 1

if your trying to solve for x then...

subtract 32 from both sides

then subtract 61 from both sides

then lastly divide by 20 on both sides

it should look like this...

[61 + 20x] + 32 > 51

[61 + 20x] + 32 -32 > 51-32

[61 + 20x] > 19

[61-61 + 20x] > 19-61

[20x] > -42

[20x/20] > -42/20

x > -2.1

Answer 2

61+20x+32>51

93+20x>51

20x>-42

x>-2.1