Another math problem! can someone please solve for me?

Question

A ship leaves the dovk moving at 24mph. Three hours later, a secong ship leaves heading in the same direction but going 32mph. How long will it take the secong ship to catch the first ship?

Answer 1

answer is 9 hour

T1=  time taken by the1st ship

T2=  time taken by the 2nd ship

T1= T2+3

distance untraveled by the ships are same

so D=24*T1=32*T2

24(T2+3)=32*T2

24T2+72=32*T2

T2=72/8 =9H

Answer 2

2 hours 10 minutes

Answer 3

There is a formula for this chase question.

The distance ÷ The difference of the two speeds = The time need to catch

So, as it is said above, the distance is 24mph×3 hours=72m

the difference of the tow speeds is (32-24)=8mph

so the time is 72÷ 8=9 hours

Answer 4

The first ship is moving at 24 miles per hour, and it got to travel for 3 hours.. that's 72 miles.

The second ship left at the 3 hour mark and is going 32 miles per hour.  Because the first ship is going 24 mph, that's a gain of 8 mph.  You take 72/8 and get 9 hours.  So 9 hours after the second ship leaves dock, it catches up with the first ship.

Answer 5

When the second ship reaches the dock, the 1st ship already had gone 72 miles. If both ships continued to move at the same rate it would take 9 hours to reach the 1st ship.

Answer 6

Let

S = distance when the second ship catches up with the first ship

The working formula is

S = Rate * Time

For the first ship,

S = 24T

and for the second ship,

S = 32(T - 3)

For the two ships to catch up with one another,

24T = 32(T - 3)

24T = 32T - 96

Rearranging,

32T - 24T = 96

8T = 96

T = 12 hours

ANSWER: The second ship will catch up with the first one 12 hours after the first ship has left the docks. Or, the second ship will catch up with the first ship 9 hours after it (second ship) leaves the docks.

Answer 7

8 hours to be tied with first ship

Answer 8

Approximately 11 hours.

Answer 9

Distance = Rate x Time

Let t = time the first ship travelled

Since the second ship left 3 hours later

time the second ship travelled = t - 3

Distance (1st ship) = Rate (1st) x Time (1st)

= 24t

Distance (2nd ship) = Rate (2nd) x Time (2nd)

= 32(t - 3)

When the second ship catches the first ship, we know that they have travelled the same distance, so we can set our two distance formulas above equal to each other.

24t = 32(t - 3)

Distribute

24t = 32t - 96

Subtract 32t from both sides

-8t = -96

Divide both sides by -8

t = 12

Answer: 12 hours

Hope this helps you!  Please email anytime for further questions.

Answer 10

distance = speed time velocity

so, first ship: d1= 24t + 72 (because 1st ship leave 3 hrs ahead with 24mph: 24*3=72)

second ship d2=32t

set d1= d2 (where 2 ship meet):

24t + 72 =32t

8t = 72

t = 9

so 9 hours.

Answer 11

Well the first ship has made 72 miles when the 2nd one has made 0... so the equation will be this one:

Plain 1= 24.h + 72    ---------------   Plain 2= 32.h +0

24h+72 = 32x+0

72-0 = 32h-24h

72=8h

9=h      

So, the second plain needs to fly 9 hours to catch the first ship!

Hope it works 4 u!!

Im sure this is the answer  ;D

Answer 12

1 Hour!!!!!!!!!!

Answer 13

Sorry I didn't narrow it down but it's going to come to a little over an hour.  I think it comes to an Hour and 14 minutes though.