Another quick question on absolute value functions?

Question

When

y=3|x-4|

what is considered b, m, and c? The 3 is throwing me off, as standard form is: y=|mx+b|+c

Thank you in advance :)

Answer 1

don't let the 3 throw you off, it is the m in the equation. With the absoulte value (x-4) it is the distance away from zero so it  would be x+4. So put it together and you get y=3x+4. To get it into standard form you have to subtract 3x and get it to the other side.So you get     -3x+y=4. I hope I helped :D

Answer 2

Hello there:

You can rewrite y = 3|x - 4| as:

y = |3x - 12|, in which case m = 3, b = -12, and c = 0.

Hope this helps! You're welcome.