Another resistor question?

Question

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Four resistors of 10.0 each are connected in parallel. A combination of four resistors of 10.0 each is connected in series along with a parallel arrangement. What is the equivalent resistance of the curcuit?

Thanks for the help guys. I hope the picture helps!

Answer 1

four in parallel are 10/4 = 2.5 ohms.

four in series are 40 ohms, plus 2.5 = 42.5 ohms.

this is so easy, I can't see any reason you didn't do it yourself!

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Answer 2

First step is to determine the equivalent resistance of the resistors in parallel.

1/Rp = 1/R1 + 1/R2 + 1/R3 + 1/R4

where

Rp = equivalent resistance of parallel resistors

R1 = R2 = R3 = R4 = 10 ohms

(1/Rp) = (1/10) + (1/10) + (1/10) + (1/10)

Doing the required algebraic procedure

Rp = 2.5 ohms

The second step is to determine the equivalent resistance of the four resistors in series.

Rs = R1 + R2 + R2 + R4

Rs = 10 + 10 + 10 + 10

Rs = 40 ohms

NOTE since the two equivalent resistances are now effectively connected in series, then the circuit's equivalent resistance is = 2.5 + 40 = 42.5 ohms