Another word problem, needed solved?

Question

The perimeter of a rectangle is 64 cm. The length is 4 cm less than twice the width. Find the length and width.

Answer 1

Perimeter = 2 (l + w)

l = w - 4

64 = 2 ( w - 4 + w)

32 = 2w - 4

36 = 2w

w = 18

Go back to the length eq

l = w - 4 = 18 - 4 = 14

hope that helps :)

Answer 2

L = 2W-4

Perimeter = 2*(2W-4)+ 2W = 64

4W-8+2W=64

6W=72

W=12

Answer 3

{1} 2L + 2W = 64 (from the definition of a perimeter and its known length)

{2} L = 2W - 4 (from the second fact given)

{3} L -2W = -4 (subtracting 2W from each side of {2})

{4} 3L = 60 (adding equations {1} and {3})

{5} L = 20cm (dividing both sides of {4} by 3)

{6} W = 12cm (substituting {5} in any of the first 3 equations and solving)