Answer Key wrong? Two resistors with values of 6.0 Ω and 12 Ω are connected in parallel.?

Question

Two resistors with values of 6.0 Ω and 12 Ω are connected in parallel. This combination is connected in series with a 2.0 Ω resistor and a 24 V battery. What is the current in the 2.0 Ω resistor?

The answer key says the answer is 2.0 A. I believe that the answer should be 4.0 A. I can't see why the key says 2.0 A. Am I missing something?

Parallel portion:

1/R tot = 1/R1 + 1/R2

1/6 + 1/12 = 3/12 = 1/4

R tot = 4

Series Resistance: 4 + 2 = 6 Ohms

I = V/R

I = 24/6 = 4 A

The two resistors in parallel would share the 4 amps. The 2 Ohm resistor would have the 4 amps to itself, IMHO.

Answer 1

Your analysis/solution is as clear and concise as it can be. The answer key is not correct.

Answer 2

Based on your description, you are right. The answer is 4A. It's possible that the answer key is based on an older edition of the book where V = 12 Ω. That happens quite often.

Answer 3

answer key is wrong....