Answer by showing your calculations?

Question

Is it true that a pebble dropped from rest falls three times farther than the second than in the first? explain by showing calculations

Answer 1

If it is dropped from rest its initial speed is 0m/s. If its speed increases by 9.8m/s^2, then after the first second if it moving 9.8m/s^2. After the second second (ha) it is moving 19.6 m/s^2. Not quite three times father but definitely faster.  

Answer 2

Yes, it is true that a pebble dropped from rest falls three times farther (not faster) in the second second than it does in the first second.

The equation for displacement, with zero initial velocity, is;

x(t) = (g/2) t²

x(1) = (g/2) 1² = g/2

x(2) = (g/2) 2² = 4(g/2)

So during the second second, that is, from t=1 to t = 2, the pebble falls a distance equal to 4(g/2) - (g/2) = 3 (g/2), which is 3 times longer than the distance it falls from t = 0 to t = 1

Answer 3

yes,true