Answer for Expanding (x-1)^3?

Question

expand (x-1)^3

With workings out

Answer 1

(x^3 - 1^3)

(x^3 -1)

the end(:

... at least if thats what youre asking for, thats all i know how to do...

sorry if im wrong:(

Answer 2

(x-1)(x-1)(x-1) =

(x-1) (x^2 - 2x + 1) =

x(x^2 - 2x + 1) - 1(x^2 - 2x + 1)

x^3 -2x^2 + x - x^2 + 2x - 1

= x^3 - 3x^2 + 3x - 1

Answer 3

it's simple

USE DISTRIBUTIVE METHOD

= (x - 1)(x - 1)(x - 1)

= (x*x - 1*x - 1*x + 1*1)(x - 1)

= (x^2 - x - x + 1)(x - 1)

= (x^2 - 2x + 1)(x - 1)

= x^2*x - 2x*x + 1*x - x^2*1 + 2x*1 - 1*1

= x^3 - 2x^2 + x - x^2 + 2x - 1

= x^3 - 2x^2 - x^2 + x + 2x - 1

= x^3 - 3x^2 + 3x - 1

then final answer is

x^3-3x^2+3x-1

here's a calculator for expanding polynomials

http://www.hostsrv.com/webmab/app1/MSP/q...

Answer 4

(x - 1)^3

= (x - 1)(x - 1)(x - 1)

= (x*x - 1*x - 1*x + 1*1)(x - 1)

= (x^2 - x - x + 1)(x - 1)

= (x^2 - 2x + 1)(x - 1)

= x^2*x - 2x*x + 1*x - x^2*1 + 2x*1 - 1*1

= x^3 - 2x^2 + x - x^2 + 2x - 1

= x^3 - 2x^2 - x^2 + x + 2x - 1

= x^3 - 3x^2 + 3x - 1