Question:

Answer for Expanding (x-1)^3?

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expand (x-1)^3

With workings out

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4 ANSWERS


  1. (x^3 - 1^3)

    (x^3 -1)

    the end(:

    ... at least if thats what youre asking for, thats all i know how to do...

    sorry if im wrong:(


  2. (x-1)(x-1)(x-1) =

    (x-1) (x^2 - 2x + 1) =

    x(x^2 - 2x + 1) - 1(x^2 - 2x + 1)

    x^3 -2x^2 + x - x^2 + 2x - 1

    = x^3 - 3x^2 + 3x - 1

  3. it's simple

    USE DISTRIBUTIVE METHOD

    = (x - 1)(x - 1)(x - 1)

    = (x*x - 1*x - 1*x + 1*1)(x - 1)

    = (x^2 - x - x + 1)(x - 1)

    = (x^2 - 2x + 1)(x - 1)

    = x^2*x - 2x*x + 1*x - x^2*1 + 2x*1 - 1*1

    = x^3 - 2x^2 + x - x^2 + 2x - 1

    = x^3 - 2x^2 - x^2 + x + 2x - 1

    = x^3 - 3x^2 + 3x - 1

    then final answer is

    x^3-3x^2+3x-1

    here's a calculator for expanding polynomials

    http://www.hostsrv.com/webmab/app1/MSP/q...

  4. (x - 1)^3

    = (x - 1)(x - 1)(x - 1)

    = (x*x - 1*x - 1*x + 1*1)(x - 1)

    = (x^2 - x - x + 1)(x - 1)

    = (x^2 - 2x + 1)(x - 1)

    = x^2*x - 2x*x + 1*x - x^2*1 + 2x*1 - 1*1

    = x^3 - 2x^2 + x - x^2 + 2x - 1

    = x^3 - 2x^2 - x^2 + x + 2x - 1

    = x^3 - 3x^2 + 3x - 1

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