Answer this question!?

Question

A coach has 20 players. How many ways can the coach select 5 players to start the game?

(Assume that any player can play any position.)

Answer 1

4 ways

Answer 2

you need a different hobbie then football

Answer 3

This is a combination problem.

20C5 = 15504

Answer 4

There are 20 players so there are 20 possibilities for the 1st player chosen.

That leaves 19 left so there 20 X 19 for the first 2 spots; 380.

For the 3rd player chosen there are 18 left, so it's 380 X 18 or 6,460.

For the 4th, there are still 17 to go, so it's now 6,460 X 17 or 116,280.

For the last spot there are 16 left.116,280 X 16 = 1,860,480 combinations!  

Answer 5

20/5=4(20posible outcomes) /by percent that gets counted twice (2)times everything else=76871876.

math teacher

Answer 6

LOL ITS 4 are u 5

Answer 7

um 20 divide by 5 is 4..how old r u?

Answer 8

20(4)(12)(24)=23040

23040 possible outcomes.

Answer 9

826880

Answer 10

Alright. easy question. 1860480

How you ask?

For questions like this, you have to follow the basic formula of [possibilities^spaces] (btw, ^ "means to tho power of" if you didn't know). For example, the number of three digit numbers using 0-9. Obviously the answer is 1000 (1-999 and zero). So 0-9 is 10 possibilities, so 10^3 is 1000. there ya go.

BUT in this question, you obviously can't put the same person in two spots. If you could, it would be 20x20x20x20x20, easy problem. but since you can't, subtract ONE from each number to the right of the original. You get 20x19x18x17x16. Put that through a calculator, and you get 1860480. There ya go. Answered and explained :P

BTW, if you wanna test the second method because you don't trust me for some reason, >:(

Say you are finding the possibilities of a 2 digit number (including 01, 02, 03), without repetition (ex. not 11), using only 0,1,and 2. so two spots. According to my theory, there are 6 possibilities. Lets count off all the possibilities. 00, 01, 02, 10, 11, 12, 20, 21, 22. There's 9. Now 00, 11, and 22 are NOT eligible, due to repitition, so 9-3=6

:P read it and weep

Answer 11

20 times.. Im pretty sure...We had this question in a math last year.