Question:

Any help on soving this problem pls?

by  |  earlier

0 LIKES UnLike

The striker in a forging machine has a mass of 1.5tonnes. During the working stroke, the striker slides down the vertical guide rails from a height of 1.5m onto the work piece. Causing it to be compresses through a distance of 50mm before coming to rest. Friction between the striker and the rail is equivalent to a vertical force of 1500n at all speeds of sliding.

Determine the average force acting on the workplace.

 Tags:

   Report

1 ANSWERS


  1. Cool problem. It uses conservation of energy, PE = mgh, and E = F*dist

    To get total energy, it is the potential energy of the striker before:

    PE = mgh = 1500kg * 9.8m/s^2*(1.5+0.050)m

    I'm not sure about adding the 50mm, but that's the way I read it.

    From that total potential energy, deduct the friction:

    Efriction = Ffriction * dist = 1500N * 1.55m

    Now, remaining energy is absorbed by workpiece:

    PE - Efriction = Fform * dist

    Where dist = 50mm, solve for Fform.

Question Stats

Latest activity: earlier.
This question has 1 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.