Any idea how to do this???

Question

write equations for the following..

1. a line with a slope of 5 and a y-intercept of -2

slope intercept: ____

standard form:_____

how do i do this??? can you show me the steps...thanks

Answer 1

Let me show you the steps so you can do this in the future.

The formula you want is:

y - y(sub 1) = M(x-x(sub 1))

Where y(sub 1) is the y-intercept and M is the slope.

So just put the information (slope = 5, and y-intercept is (0,-2) in the formula:

y - (-2) = 5(x-0)

Notice that I put a 0 in the place of the x(sub 1) since (0,-2) was given in the question.

Now solve for y to get

y + 2 = 5x - 0

y = 5x -2

This is the slope intercept form.

And rewrite the equation for the standard form:

5x - y = 2

Hope this helps.

Have a good day!

Answer 2

Have a look at this:

http://www.college-cram.com/study/algebr...

Answer 3

Slope int is y = mx+b. You have both m which is the slope and b which is the y-int.

slope-int: y = 5x - 2

Std form moves the integer values of x and y to one side and the constant to the other side.

Std: 5x - y = 2

Answer 4

Okay your standard equation is

y = mx + b

where m is the slope

y intercept is b because

you get the y intercept whenever you substitute x = 0.

y = 0.x + b

y = b

Thats why b is your y intercept..

You can also find the x intercept of an equation if you plug in y = 0 which would be

0 = mx + b

x = -b/m

Equation is therefore y = 5x - 2 :)

for standard bring all the variables together

y - 5x = -2 :)

hope this helps :)