Are the following functions odd, even, or neither?

Question

y= square root of x

y= 3 the square root of x

y= 1/x

y=1/x^2

and if anybody knows any good math sites that would be awesome!!

Answer 1

A function is even if

f(x) = f(-x)

and odd if

f(x) = -f(-x)

1. f(x) = sqrt(x)

f(-x) = sqrt(-x) = i f(x)

The function is neither odd or even.

2. f(x) = cube_root(x)

f(-x) = cube_root(-x) = - cube_root(x) = -f(x)

The function is odd.

3. f(x) = 1/x

f(-x) = 1/(-x) = - (1/x) = -f(x)

The function is odd.

4. f(x) = 1/x^2

f(-x) = 1/(-x)^2 = 1/x^2 = f(x)

The function is even.