Area under the curve ?

Question

Need help with this Calc problem please. approx. the area under the curve y=4-(x^2 /16)between x=0 and x=8 by using 4 rectangles and right hand end points.

Thank youuuu

Answer 1

This is a parabola with its head at the point (8,0) cuts the y axis at -ve 4 and +ve 4.

The graph is  f(x) = 4-(x^2 /16)

Now, we have 4 rectangles, then we will get 4 terms in the range of units.

Then "delta x" = 2 , call dx

Area under curve :

A = (Summation mark )   f(2) * 2 +   f(4) * 2 +  f(6) * 2 +  f(8) * 2

    =  3.75 * 2 +   3 * 2 +  1.75 * 2 +  0 * 2

    = 17.

Check the answers again, for practice.

Good luck

    

Answer 2

You have to draw the graph of the curve and you will understand how to do it.