As x gets arbitarily large in a negative way, k(x)=x -square approaches:?

Question

infinity

-infinity

0

you cannot take the suare root of a negative quantity

Answer 1

do you mean k(x) = x^2? If you do that'd be a parabola and if x gets large in a negative way (smaller)...well let's see...

k(-5) = (-5)^2 = 25

k(-10) = 100

k(-1000) = 1000000

k(-1000000000) = 1000000000000000000000000

it appears it approaches infinity

as far as the last choice goes "...root of a negative quantity" I dunno. That's why I tend to think I misunderstood the problem. Feel free to proofread.