At 35 degrees C, the value of Kw is 2.09 x 10-14.

Question

Determine the pH of water at this temperature. What does the term neutral mean at 35 degrees C?

Answer 1

H2O<--> H+  +OH-  

for electroneutrality [H+]=[OH-] .this is neutrality

so [H+]^2= [H2O]*Kw

[H2O]=1000/18 =55.6

so [H+]^2 =55.6*2.09*10^-14 =1.16*10^-12

[H+]=1.078*10^-6

pH= log1/[H+)= 5.97