At what points do the lines 2x+8=5y and 3y-5=x intersect?

Question

I never really learned how to do this type of problem with linear equations and I need help! Thanks!

Answer 1

substitute x in the first equation from the second equation. so you get

2(3y-5)+8=5y

6y-10+8=5y

6y-2=5y

y=2

then substitute y back into either equation to get the value of x

3(2)-5=x

6-5=x

x=1

hope this helps!!!!!!!

Answer 2

hehe. I remember doing this last year. I already know the answer.

First, you must  isolate x from 2x+8=5y. (get x on one side ex: x=rest of eqaution) luckily 3y-5=x is already done for you.

i also found this website just in case i'm wrong :]

Answer 3

1) set both equations into y intercept form

2x/5 + 8/5 = y and y = x/3 + 5/3

2) set both equations to each other. This works because at the point of intersection both equations will have the same y and x values.

2x/5 + 8/5 = x/3 + 5/3

3) subtract x/3 and 8/5 from both sides

2x/5 -x/3 = -8/5 + 5/3

4)multiply 2/5 by 3/3, -x/3 by 5/5, -8/5 by 3/3, 5/3 by 5/5

6x/15 - 5x/15 = -24/15 + 25/15

x/15 = 1/15

5) multiply both sides by 15

6)x = 1

7) plug into  one of the original equations

y = 1/3 + 5/3 = 6/3 = 2

point is (1,2)