At what temperature will 0.654 moles of neon gas occupy 12.30 liters at 1.95 atmospheres?

Question

At what temperature will 0.654 moles of neon gas occupy 12.30 liters at 1.95 atmospheres?

Answer 1

one billion degrees.  now get out your book and verify my calculation.

Answer 2

use mole concept n find it out

Answer 3

1.95(12.3)=.654(.0821)(T)? Dude, it's been like 3 months since AP chem.. no idea if that's right.

Answer 4

PV=nRT

T = PV/nR

T = 1.95 atm x 12.30 L / (0.654 mol x 0.08206)

T = 446.9 deg K