Question:

At which temperature do both Centigrade and Fahrenheit show the same reading?

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..its our science quiz!! HELP!! =]

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  1. why do some people put overly complex answers instead of -40? what a waste of time


  2. -40

    Whilst the equations are both linear, if you were to plot them both on the same graph, you would see that the results do intersect (at -40degrees).

    Another, slightly more geeky, way to get the answer is to use the 2 equations

    1. F=9/5C +32 ... used to convert from centigrade (Celsius) to Fahrenheit

    2. C= 5/9(F- 32).... used to convert from Fahrenheit to Centigrade (Celsius)

    Firstly write the write the equations so that they are equal (C=F), and then we can solve the simultaneous equations. So it looks like this:

    9/5C+32 = 5/9(F-32). (this is when Fahrenheit and Celcius/ Centigrade are equal)

    Then you solve for either F or C, by substituting for either F or C into the equation above (1. if you are solving for F, or 2. if you are solving for C) lets use number 1 and solve for F

    It now looks like this:

    9/5C+32 = 5/9((9/5C+32)-32) (I just put in (9/5C + 32), where F used to be.

    To solve it we just use some simple rules of equations to try to get C on its own

    Firstly divide both sides by 5/9) and it look like this:

    9(9/5C+32)/5 = ((9/5C+32)-32)

    Then simplify right hand side by removing the brackets like this:

    9(9/5C+32)/5 = 9/5C [of course 32-32=0]

    Next simplify the left hand side by opening brackets (it is done by multiplying everything inside the brackets by 9):

    (81/5C+288)/5 = 9/5C

    To get rid of 5 on bottom of left hand side, you muliply both sides by 5 and get:

    (81/5C+288) = 45/5C

    Next remove the brackets arent needed (nothing to do outside the brackets):

    81/5C+288 = 45/5C

    Next move Cs together and numbers to other side (by taking 288 from both sides and taking 45/5C from both sides), and it looks like this:

    81/5C-45/5C =-288

    Now solve the left hand side (easy as they are both over 5C), so its just 81-45:

    36/5C=-288

    Next multiply both sides by 5 (gets rid of the 5 on the bottom of left hand side) and you get:

    36C=-1440

    Now we divide both sides by 36 (makes C= to 1), and we get:

    C=-1440/36

    Now whack that into a calculator and Hey Presto:

    C=-40

    (it also work if you substitute for C)

    So the temperature at which Celcius = Fahrenheit is -40 degrees

    (I hope this helped)

  3. It's possible, the reading is -40.

  4. -40 degrees

  5. (F-32)/180=(C-0)/100 it is the formula for conversion between celcius and farenheit. when both are having same reading then F=C. So,

    (F-32)=F*180/100

    10F-320=18F

    8F=--320

    F=-40

    So at -40 degree both scale read same.

  6. They never do because they are different scales

  7. At -40°.

    (-40°C x 1.8) + 32 = (-72 + 32) = -40°F

    (-40°F - 32) / 1.8 = (-72 / 1.8) = -40°C

    Who the h**l gave this a thumbs down, whover you are you're a perfect Prat. No answer given is more correct than this.

  8. -- 40 C = -- 40 F

  9. They never do....

    [Edit] - how stupid do I feel now, yes, it's -40

    Hey, stop with the Thumbs down, I've already admitted that I'm a dumbass...

    -43   -45.4

    -42   -43.6

    -41   -41.8

    -40   -40

    -39   -38.2

    -38   -36.4

    -37   -34.6

  10. its -40 degrees

  11. minus 40 is the same on both scales.

  12. F=1.8C +32

    substituting F = C

    C = 1.8C + 32

    -32 = 1.8C - C

    -32 = 0.8C

      C = -32/8

      C = -40

    so,

    Celsius and Fahrenheit are equal at -40

    Note: It can also be proved using the other equation:

    C = ( F - 32 ) / 1.8

  13. -40

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