Atoms of nitrogen in 1.2G of aspartame(C14H18N2O5)

Question

HOW MANY ATOMS OF NITROGEN ARE IN 1.2GRAMS OF ASPARTAME WHICH IS C14H18N2O5 WITH MOLAR MASS OF 294G?

Answer 1

no of moles in aspartame =mass/molar mass=1.2/294=0.00408mols

no of molecules=0.00408* avagadros no.=0.00408*6.022*10^23=0.02456*10^23

no. of atoms =no.of molecules*2(coz 2 atoms of nitrogen are present)=0.02456*10^23*2=

Answer 2

one mole of drug has 2xavagadros no of atoms of nitrogen. So do 1.2/294 then multiply by 2 times avagadros no.