Attention there is a fake!?

Question

Ok, so there is someone who has been posing as Miley Cyrus and has been lying and making Miley look bad!

[e-mail] is NOT MILEY

she/he is a poser. Please do not e-mail this fake! I am letting everyone know,because I don't want other people thinking it's really her. My other friends will post this exact same question so EVERYONE gets the message. Oh and if you e-mail her about that picture that he/she calls "proof" well I have the same picture. I also have other things that has happened that makes me know she/he is a poser. I was just letting everyone know!!

THANKS FOR READING!

Answer 1

i would think miley looks bad without this persons help.

Answer 2

who cares?

besides, I heard Miley Cyrus was involved in the killing of a chimpanzee in Korea.

An innocent chimpanzee.

Answer 3

ya i know the person that gave you her e-mail so he/she can see what you write to miley!

Answer 4

If someone is stupid enough to think that the actual Miley Cyrus is over here posting on Yahoo Answers, then they deserve what they get.

Answer 5

This isn't a question; it's a rant.

Even a poser can't make Muley Cyrus look bad.  She can do that all by herself.  Stop defending her. SHE'S a fake.

Answer 6

Okay:)

thanks for telling us!

Answer 7

Thanks for letting me know, I now know not to e-mail he\she cuz he\she is a poser.

Answer 8

miley cyrus is a ******

Answer 9

how did u and ur 9 year old friends get yahoo accounts?

no one cares and is stupid enough to beleive thats miley

stop spamming kthnxbye

Answer 10

Miley Cyrus is a rard anyway

Shes already made ehrself look bad in my opinion by being fake anywayso this person who is posing as her is probably making her look better in a way   =)

Answer 11

I don't care. Why would Miley Cyrus e-mail someone anyway. You can always tell this is a fake because a famous person won't just e-mail anyone.

Answer 12

Miley doesn't need her to look bad, she does that on her own and if i could thumbs up you gyrene i would

Answer 13

okey dokey then.